ICFRE Scientist Group I, II, III Recruitment 2019
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| ICFRE Scientist Group I, II, III Recruitment 2019- Indian Council of Forestry Research and Education (ICFRE) has invited Online Application Form for the post of Scientist. There are total 54 vacancies for this recruitment. You can check here important details such as- last date, exam date and admit card date for Icfre scientist group i, ii, iii online form 2024-2025 in simple steps. Application started from date 01/Apr/2019. Last date to fill this form is - 15/May/2019 so fill your form before 15/May/2019. Monthly PayScale(Salary) for this job will be -.56,100/--1,77,500/-₹. You can download this job detail by saving as pdf on your mobile/laptop device for future reference. Read instructions carefully to apply online for Scientist Application Form. If you are interested in this job you can get important details below Like- Eligibility, Form Fee, Salary etc. If you have any query related to this job, please ask in comment section. Indian Council of Forestry Research and Education (ICFRE) ने Scientist के पद के लिए ऑनलाइन आवेदन पत्र आमंत्रित किया है। इस भर्ती के लिए कुल 54 रिक्तियां हैं। आप यहां महत्वपूर्ण विवरण जैसे कि अंतिम तिथि, Scientist ऑनलाइन फॉर्म के लिए महत्वपूर्ण तारीख देख सकते हैं। इस भर्ती के फॉर्म की शुरू होने की तारीख 01/Apr/2019 है। इस फॉर्म को भरने की अंतिम तिथि है- 15/May/2019 तो 15/May/2019 से पहले अपना फॉर्म जरूर भरे। मासिक पेस्केल (वेतन) इस नौकरी के लिए .56,100/--1,77,500/- ₹ होगा। Scientist के लिए ऑनलाइन आवेदन करने के लिए सावधानीपूर्वक सभी निर्देश पढ़ें। यदि आप इस नौकरी में रुचि रखते हैं तो आप कृपया अहम् जानकारी जैसे योग्यता, फॉर्म शुल्क, वेतन आदि चेक करना मत भूले। यदि आपके पास इस नौकरी से संबंधित कोई प्रश्न है तो नीचे दिए गए कमेंट बॉक्स में पूछे! हमारी टीम आपकी पूरी मदद करेगी। Job Location - All India |
Post Name
- Scientist
ICFRE Scientist Group I, II, III Recruitment 2019 - Online Application | Job | Apply Online
You can get Detailed Description Step By Step below-
Important details | Vacancy | Selection Process
| Total Vacancy(कुल रिक्ति) | 54 |
| Min Pay Scale Monthly(न्यूनतम वेतनमान मासिक) | Rs..56,100/- |
| Pay Scale(वेतनमान) | Rs..56,100/--1,77,500/- |
| Max Pay Scale Monthly(अधिकतम वेतन स्केल मासिक) | Rs.1,77,500/- |
| Age Limit(आयु सीमा) | Min - 21 Years Max - 35 Years |
| Selection Process(चयन प्रक्रिया) | Written Exam | Interview |
Important Dates | Form Last Date
| Application Opening Date(आवेदन शुरू होने की तारीख) | 01/Apr/2019 |
| Application Closing Date(आवेदन समाप्ति तिथि) | 15/May/2019 |
Application Fee
| General(सामान्य) | Rs.1500 |
| OBC(अन्य पिछड़ा वर्ग) | Rs.1500 |
| SC(अनुसूचित जाति) | Rs.Nil |
| ST(अनुसूचित जनजाति) | Rs.Nil |
| Payment Mode(भुगतान का प्रकार) | Pay the exam fee through Debit,Credit card & online banking. |
Eligibility Criteria
Candidates who have M.SC, BE, B.Tech, ME, M.Tech, Ph.D. degree from the any recognized Board/university can apply for this post. |
Age limit
Candidates age should be in between 21-35 Years. Age Relaxation:- Refer official notification. |
Vacancy Details
Name of the post and vacancies:-
Group wise vacancy:-
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How To Apply?
You can follow Below Steps to Apply For this Job.
- STEP 1 :To Apply for Indian Council of Forestry Research and Education (ICFRE) - Scientist job Go to url - http://recruitment.icfre.gov.in/home.
- It will look something like this-
- STEP 2 : Click on "click here for new registration".
- STEP 3 : if already registered Enter "Registration No"Date of Birth"captcha" and click on "submit" button.
- STEP 4 : fill the form pay the fee and submit
- Note : Candidates are advised to read notification prior to apply for the post.
Apply Online | Notification Download | Quick Links
| Apply Online(फार्म भरें) | CLICK HERE |
| Download Notification(अधिसूचना डाउनलोड करें) | CLICK HERE |
| Official Website(आधिकारिक वेबसाइट) | CLICK HERE |
| Download App [ For Latest Updates Download Our Andriod App ] | CLICK HERE |
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| ✍ Previous Year Paper | CLICK HERE |
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